The vast expanses of empty space within the nuclear atom cannot possibly provide a base on which to build any kind of solid structure. It can be justifiably laid to rest, I think.
The neutron contributes nothing to the size of an atom because the charge structure within is entirely balanced. Theoretically, the container and its contents can shrink to point size.
The theory predicts that protons in contact make up the entire volume of an element, and that proton-proton contact will be made at some point between atoms of a solid.
Clearly, the elements are still forming in the same mode as they did at the beginning of time, otherwise there would be elements with the same atomic number having entirely different properties.
The positive charge of the proton originates from its interior. An electron will always be directionally located relative to the proton charge. The charge dipole between the electron and positive charge of the proton will be counteracted when the hydrogen molecule is formed because the whole charge structure would develop a bond between the opposites and the group of charges would close together until contact is made between the proton surfaces.
The charge interaction in the association would finally become very tightly formed in the center between the two protons, but because the whole charge structure cannot be drawn inward to a point, there will still be minor charge dipoles appearing in the world outside the association. The point sized electrons can be drawn inward to a greater degree than the positive charge of the proton, so the outermost ends of the two dipoles will carry a positive charge, which will resist bonding between similar molecules. The proton charge obviously isn't generated by one specific positron either. That instability would be in perpetual resonance throughout the proton body. The positive end of the dipoles would extend into the proton body to some degree as well.
Because the charge structure apparently determines all of the properties of the elements, there is a logical direction of development for them. The charge structure would always be the same between a specific number of protons grouped together in the same pattern, and the pattern would be created in the same mode if the charge structure from one stage of the group development determines the next direction.
To simulate this development I glued steel balls into that which appeared to be the most logical location for each new input proton, being always in a depression where the electrons reside, in the innermost part of the charge structure of the element.
The stages to lithium were obvious.
The next proton input (naturally accompanied by an electron) added to lithium will be on one side of the three group, and the next two, probably on the same face, creating a lithium twin pack, with a neutron connection, creating the carbon atom.
There would be one location on the carbon atom that would be more favourable toward the next input. The current atomic design would determine this location. Once one location has a proton/neutron fused into the atom the arrangement and accessibility of the inner charge structure will be altered. When three more locations have been filled, the charge interaction apparently becomes confined within the atomic structure, leaving the outer of the surface protons with very little charge. The logical placement of steel balls suggested that the neon atom would be a pyramid shape, having four, three cornered faces.
The fusion of one proton into the center of each face of the neon atom creates a precise cube consisting of fourteen protons.
Similar to the carbon atom, the next input will be applied to any of the vacancies on any face of the silicon atom. The charges of the new input will interact with the previous charge structure of the atom, disturbing the symmetry. The electron accompanying the newly input proton is again able to be drawn inward to a greater degree than the charge of its parent proton, leaving the proton with a slight positive charge extending into the outside world.
The next three inputs are on the same face, filling all charge accessible locations that were opened up by the first input to that face. Every opening that had revealed any of the charge structure has now apparently been filled and the charge structure is once again all confined within the argon atom.
The first input to the argon atom will fill one of the cavities in one end of the atom and this rearranges the charge structure as did the first input to the neon atom, opening up some charge structure to the outside world. The next thirteen inputs will be located in a specific pattern on the one end, or perhaps on both ends, until the most charge accessible areas have been filled. The element shape is now similar to the silicon atom, being two silicon cubes, with four protons connecting them.
As with the sequence from silicon to argon, four more inputs on one end of the germanium atom creates the extended argon atom, krypton.
Xenon is created in the same manner as was krypton. This becomes a three pack of the silicon atom, each connected by four protons (tin), with the additional four inputs on one end, as was present on the ends of the argon and krypton atoms.
If the first proton fused into one of the four faces of the neon atom is not included in the main body of the charge structure the electron will be restrained only by its positive counterpart. If both charges in that dipole are accessible to the outside world the electron could easily be ejected and replaced by another free electron that's on the move.
The last input proton will be one part of the contact point between contacting atoms of a solid because this is where the atomic charge structure is most accessible and the logical first point of association with other atoms. Electrons can then be shifted through the contact points.
The following two inputs will be similarly attached, so each of these inputs will also be a point of contact with other atoms that carry accessible charges. The number of group 7 elements, which apparently contain only one accessible charge location each, that can be attached to these atoms indicates that these inputs are the contact points between atoms of a solid. The maximum number of chlorine atoms that can attach to phosphorus is five, again indicating that the external inputs to the neon atom are the (solid) points of contact with other atoms.
The whole element development follows the same square pillar shape, extending in length with each series of inputs, following a specific reoccurring pattern that changes exactly with the character of the elements. But the system seems to break down somewhere in the Lanthanide Series. Argon, krypton and xenon are all similar in design, as are the semiconductor elements. The radon shape, due to its proton content, will be a square pillar and would be the equivalent of an extended silicon atom, being five silicon atoms in length, connected by four protons between each. This doesn't contain the same end shapes that were present in the other noble gases. Hafnium is also incorrectly designed compared with an equivalent in the lighter elements. The proton content suggests that this would be the next noble gas element, built on what was expected to be the next semiconductor element, and that it would have the same end shapes as argon, krypton and xenon, The fact that astatine forms into a diatomic molecule is another reason to expect its atomic design to be comparable with the other elements of that group. They are all consistently in error by four protons.
If the attractive forces through the growing length of the square pillar become so great that, in a fusion environment, and at a specific stage of development, four protons in a section close to the center of the pillar collapse into the neutron state, all in the same reaction, the correct end shapes will develop for all of the following elements.
Developing through the Lanthanide Series, the characters of the elements don't greatly alter. However, the character change at the end of the series suggests that some distinct change occurs somewhere around this point. If the four proton collapse to neutrons occurs at the stage that creates hafnium this must have occurred when the proton content was four more than that of hafnium, requiring there to be two different elements for hafnium, and for each of the three following elements on the periodic table. The sister element being of the rare-earth type.
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Perhaps these four extra elements do exist. We have never had the need to find them.
The different products of uranium fission suggest that these product elements are already formed within the pillar of the uranium atom, with the break point being the point at which the four proton collapse to neutrons had occurred. The location of the collapse would be the weakest link because it will be the break point of the charge structure, and is also the location of neutron abundance.
The products of uranium fission and the positioning of the six protons on the radon atom, with the corrected end shapes, that create uranium give an insight to the pattern of development for some elements. Only one direction can satisfy all criteria.
When the pillar is broken in a four unit section, that will create Sn and Mo, the Sn product will contain a "semiconductor" five group on each end. The Mo product will contain the same end shapes as uranium.
If the products of fission are Sn & Mo, the four proton collapse was all within a four proton section of the pillar. If the products are Ba & Kr, or Xe & Sr, the four proton collapse was in a five proton section. The remaining not converted proton of the five group would be located centrally between the groups of four on either side of the collapse and, at the time of the break, would align with and be included in the charge structure of one section more than the other, in the appropriate position within a naturally occurring atomic shape of one end. The center proton of a five group would be shielded from the energy of a fusion environment by the surrounding outer structure, hence the non conversion. The Kr or Xe product will have the outer five unit end of the uranium atom and a four proton end from the break point. The Ba or Sr will contain the other end of the uranium atom and four protons from the break point, plus the single remaining proton at the break point.
The original development of an element, from Kr to Sr, or from Xe to Ba, being additional two inputs in each case, in order to align with the product shapes from the fission, the first input will be attached to the five group end of the noble gas atom, and the next located in the center of the four group end. Continuing on from this stage, four more inputs around the last input to the center of the four group end will create, Mo from Kr, Nd from Xe. The end shapes of each would then be as uranium.
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